F(x)=-0.0025x^2+x+3

Solution for F(x)=-0.0025x^2+x+3 equation:

(F)=-0.0025F^2+F+3

We move all terms to the left:

(F)-(-0.0025F^2+F+3)=0

We get rid of parentheses

0.0025F^2-F+F-3=0

We add all the numbers together, and all the variables

0.0025F^2-3=0

a = 0.0025; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·0.0025·(-3)
Δ = 0.03
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.03}}{2*0.0025}=\frac{0-\sqrt{0.03}}{0.005}
=-\frac{\sqrt{}}{0.005}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.03}}{2*0.0025}=\frac{0+\sqrt{0.03}}{0.005}
=\frac{\sqrt{}}{0.005}
$